Base | Representation |
---|---|
bin | 100000000001111100011… |
… | …0101001011111100000001 |
3 | 120120211220100211212220012 |
4 | 1000003320311023330001 |
5 | 1034111222112000301 |
6 | 13210204050154305 |
7 | 633023100553163 |
oct | 100037065137401 |
9 | 16524810755805 |
10 | 4402221203201 |
11 | 1447a76115898 |
12 | 5b121ab82995 |
13 | 25c1876803a3 |
14 | 1130d64dc933 |
15 | 797a28acebb |
hex | 400f8d4bf01 |
4402221203201 has 2 divisors, whose sum is σ = 4402221203202. Its totient is φ = 4402221203200.
The previous prime is 4402221203183. The next prime is 4402221203203. The reversal of 4402221203201 is 1023021222044.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2468744858176 + 1933476345025 = 1571224^2 + 1390495^2 .
It is a cyclic number.
It is not a de Polignac number, because 4402221203201 - 214 = 4402221186817 is a prime.
Together with 4402221203203, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (4402221203203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2201110601600 + 2201110601601.
It is an arithmetic number, because the mean of its divisors is an integer number (2201110601601).
Almost surely, 24402221203201 is an apocalyptic number.
It is an amenable number.
4402221203201 is a deficient number, since it is larger than the sum of its proper divisors (1).
4402221203201 is an equidigital number, since it uses as much as digits as its factorization.
4402221203201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 4402221203201 its reverse (1023021222044), we get a palindrome (5425242425245).
The spelling of 4402221203201 in words is "four trillion, four hundred two billion, two hundred twenty-one million, two hundred three thousand, two hundred one".
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