Base | Representation |
---|---|
bin | 1100110100000000110… |
… | …10101000111110000111 |
3 | 1120002100011100122120212 |
4 | 12122000122220332013 |
5 | 24203103212201044 |
6 | 534124411150035 |
7 | 43543404605546 |
oct | 6320032507607 |
9 | 1502304318525 |
10 | 440241131399 |
11 | 15a783706a93 |
12 | 713a3a4531b |
13 | 3268c6496b4 |
14 | 174447bc15d |
15 | b6b9661a9e |
hex | 66806a8f87 |
440241131399 has 2 divisors, whose sum is σ = 440241131400. Its totient is φ = 440241131398.
The previous prime is 440241131353. The next prime is 440241131453. The reversal of 440241131399 is 993131142044.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 440241131399 - 212 = 440241127303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (440241131339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220120565699 + 220120565700.
It is an arithmetic number, because the mean of its divisors is an integer number (220120565700).
Almost surely, 2440241131399 is an apocalyptic number.
440241131399 is a deficient number, since it is larger than the sum of its proper divisors (1).
440241131399 is an equidigital number, since it uses as much as digits as its factorization.
440241131399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 41.
The spelling of 440241131399 in words is "four hundred forty billion, two hundred forty-one million, one hundred thirty-one thousand, three hundred ninety-nine".
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