4404125131253 has 2 divisors, whose sum is σ = 4404125131254. Its totient is φ = 4404125131252.

The previous prime is 4404125131169. The next prime is 4404125131267. The reversal of 4404125131253 is 3521315214044.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4170017211844 + 234107919409 = 2042062^2 + 483847^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4404125131253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4404125631253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2202062565626 + 2202062565627.

It is an arithmetic number, because the mean of its divisors is an integer number (2202062565627).

Almost surely, 2^{4404125131253} is an apocalyptic number.

It is an amenable number.

4404125131253 is a deficient number, since it is larger than the sum of its proper divisors (1).

4404125131253 is an equidigital number, since it uses as much as digits as its factorization.

4404125131253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 35.

The spelling of 4404125131253 in words is "four trillion, four hundred four billion, one hundred twenty-five million, one hundred thirty-one thousand, two hundred fifty-three".