44042040114133 has 2 divisors, whose sum is σ = 44042040114134. Its totient is φ = 44042040114132.

The previous prime is 44042040114097. The next prime is 44042040114143. The reversal of 44042040114133 is 33141104024044.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40019199601329 + 4022840512804 = 6326073^2 + 2005702^2 .

It is a cyclic number.

It is not a de Polignac number, because 44042040114133 - 2³³ = 44033450179541 is a prime.

It is a super-3 number, since 3×44042040114133³ (a number of 42 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 44042040114095 and 44042040114104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44042040114143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22021020057066 + 22021020057067.

It is an arithmetic number, because the mean of its divisors is an integer number (22021020057067).

Almost surely, 2^{44042040114133} is an apocalyptic number.

It is an amenable number.

44042040114133 is a deficient number, since it is larger than the sum of its proper divisors (1).

44042040114133 is an equidigital number, since it uses as much as digits as its factorization.

44042040114133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 44042040114133 its reverse (33141104024044), we get a palindrome (77183144138177).

The spelling of 44042040114133 in words is "forty-four trillion, forty-two billion, forty million, one hundred fourteen thousand, one hundred thirty-three".