Base | Representation |
---|---|
bin | 100000000011010000110… |
… | …0100010100011110001101 |
3 | 120121010012122201221001211 |
4 | 1000012201210110132031 |
5 | 1034133021321144323 |
6 | 13211353014534421 |
7 | 633153204213466 |
oct | 100064144243615 |
9 | 16533178657054 |
10 | 4405052131213 |
11 | 14491990a7a18 |
12 | 5b188b067411 |
13 | 25c519018b16 |
14 | 1132c4493d6d |
15 | 798bb1a670d |
hex | 401a191478d |
4405052131213 has 2 divisors, whose sum is σ = 4405052131214. Its totient is φ = 4405052131212.
The previous prime is 4405052131159. The next prime is 4405052131219. The reversal of 4405052131213 is 3121312505044.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4021200015849 + 383852115364 = 2005293^2 + 619558^2 .
It is a cyclic number.
It is not a de Polignac number, because 4405052131213 - 225 = 4405018576781 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4405052131219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2202526065606 + 2202526065607.
It is an arithmetic number, because the mean of its divisors is an integer number (2202526065607).
Almost surely, 24405052131213 is an apocalyptic number.
It is an amenable number.
4405052131213 is a deficient number, since it is larger than the sum of its proper divisors (1).
4405052131213 is an equidigital number, since it uses as much as digits as its factorization.
4405052131213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 4405052131213 its reverse (3121312505044), we get a palindrome (7526364636257).
The spelling of 4405052131213 in words is "four trillion, four hundred five billion, fifty-two million, one hundred thirty-one thousand, two hundred thirteen".
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