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4405052241943 is a prime number
BaseRepresentation
bin100000000011010000110…
…0100101111100000010111
3120121010012122221112221221
41000012201210233200113
51034133021333220233
613211353021151211
7633153205154353
oct100064144574027
916533178845857
104405052241943
111449199173131
125b188b0bb507
1325c519057342
141132c44c2463
15798bb1c942d
hex401a192f817

4405052241943 has 2 divisors, whose sum is σ = 4405052241944. Its totient is φ = 4405052241942.

The previous prime is 4405052241881. The next prime is 4405052242039. The reversal of 4405052241943 is 3491422505044.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4405052241943 - 217 = 4405052110871 is a prime.

It is a super-3 number, since 3×44050522419433 (a number of 39 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4405052241943.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4405052221943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2202526120971 + 2202526120972.

It is an arithmetic number, because the mean of its divisors is an integer number (2202526120972).

Almost surely, 24405052241943 is an apocalyptic number.

4405052241943 is a deficient number, since it is larger than the sum of its proper divisors (1).

4405052241943 is an equidigital number, since it uses as much as digits as its factorization.

4405052241943 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 43.

Adding to 4405052241943 its reverse (3491422505044), we get a palindrome (7896474746987).

The spelling of 4405052241943 in words is "four trillion, four hundred five billion, fifty-two million, two hundred forty-one thousand, nine hundred forty-three".