Base | Representation |
---|---|
bin | 10100000010000011100100… |
… | …10110101010000110011001 |
3 | 12202222020121010011200202111 |
4 | 22001001302112222012121 |
5 | 21233213124400130014 |
6 | 233404444123432321 |
7 | 12164405254353103 |
oct | 1201016226520631 |
9 | 182866533150674 |
10 | 44051103130009 |
11 | 13043a71341688 |
12 | 4b354953856a1 |
13 | 1b7700283b461 |
14 | ac4128860573 |
15 | 515d0c3202c4 |
hex | 2810725aa199 |
44051103130009 has 2 divisors, whose sum is σ = 44051103130010. Its totient is φ = 44051103130008.
The previous prime is 44051103129997. The next prime is 44051103130057. The reversal of 44051103130009 is 90003130115044.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32116475779600 + 11934627350409 = 5667140^2 + 3454653^2 .
It is a cyclic number.
It is not a de Polignac number, because 44051103130009 - 219 = 44051102605721 is a prime.
It is not a weakly prime, because it can be changed into another prime (44055103130009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22025551565004 + 22025551565005.
It is an arithmetic number, because the mean of its divisors is an integer number (22025551565005).
Almost surely, 244051103130009 is an apocalyptic number.
It is an amenable number.
44051103130009 is a deficient number, since it is larger than the sum of its proper divisors (1).
44051103130009 is an equidigital number, since it uses as much as digits as its factorization.
44051103130009 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 31.
The spelling of 44051103130009 in words is "forty-four trillion, fifty-one billion, one hundred three million, one hundred thirty thousand, nine".
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