Base | Representation |
---|---|
bin | 10100000010100011001000… |
… | …00001001111010010101111 |
3 | 12210000212022122121000112001 |
4 | 22001101210001033102233 |
5 | 21234002322340101333 |
6 | 233420325041153131 |
7 | 12165545113560145 |
oct | 1201214401172257 |
9 | 183025278530461 |
10 | 44068042503343 |
11 | 13050174161581 |
12 | 4b3882232b7a7 |
13 | 1b787a20c55a1 |
14 | ac4c9447b595 |
15 | 51649e51db7d |
hex | 28146404f4af |
44068042503343 has 2 divisors, whose sum is σ = 44068042503344. Its totient is φ = 44068042503342.
The previous prime is 44068042503281. The next prime is 44068042503377. The reversal of 44068042503343 is 34330524086044.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 44068042503343 - 225 = 44068008948911 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 44068042503293 and 44068042503302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44068042503143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22034021251671 + 22034021251672.
It is an arithmetic number, because the mean of its divisors is an integer number (22034021251672).
Almost surely, 244068042503343 is an apocalyptic number.
44068042503343 is a deficient number, since it is larger than the sum of its proper divisors (1).
44068042503343 is an equidigital number, since it uses as much as digits as its factorization.
44068042503343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3317760, while the sum is 46.
Adding to 44068042503343 its reverse (34330524086044), we get a palindrome (78398566589387).
The spelling of 44068042503343 in words is "forty-four trillion, sixty-eight billion, forty-two million, five hundred three thousand, three hundred forty-three".
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