Base | Representation |
---|---|
bin | 100000000110000101101… |
… | …0000010100101010110111 |
3 | 120121200212112221212021011 |
4 | 1000030023100110222313 |
5 | 1034232433240210320 |
6 | 13214235103333051 |
7 | 633456446254603 |
oct | 100141320245267 |
9 | 16550775855234 |
10 | 4411120241335 |
11 | 1450822418965 |
12 | 5b2aa32b1187 |
13 | 25cc75241122 |
14 | 1136dc352503 |
15 | 79b23c9505a |
hex | 4030b414ab7 |
4411120241335 has 32 divisors (see below), whose sum is σ = 5660956631232. Its totient is φ = 3287995852800.
The previous prime is 4411120241321. The next prime is 4411120241377. The reversal of 4411120241335 is 5331420211144.
It is a happy number.
It is not a de Polignac number, because 4411120241335 - 25 = 4411120241303 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4411120241297 and 4411120241306.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 74599852 + ... + 74658958.
It is an arithmetic number, because the mean of its divisors is an integer number (176904894726).
Almost surely, 24411120241335 is an apocalyptic number.
4411120241335 is a deficient number, since it is larger than the sum of its proper divisors (1249836389897).
4411120241335 is a wasteful number, since it uses less digits than its factorization.
4411120241335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67923.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 4411120241335 its reverse (5331420211144), we get a palindrome (9742540452479).
The spelling of 4411120241335 in words is "four trillion, four hundred eleven billion, one hundred twenty million, two hundred forty-one thousand, three hundred thirty-five".
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