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4411120251413 is a prime number
BaseRepresentation
bin100000000110000101101…
…0000010111001000010101
3120121200212112222101002102
41000030023100113020111
51034232433241021123
613214235103451445
7633456446326151
oct100141320271025
916550775871072
104411120251413
111450822425497
125b2aa32b6b85
1325cc752458a5
141136dc356061
1579b23c98028
hex4030b417215

4411120251413 has 2 divisors, whose sum is σ = 4411120251414. Its totient is φ = 4411120251412.

The previous prime is 4411120251409. The next prime is 4411120251427. The reversal of 4411120251413 is 3141520211144.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4219873218289 + 191247033124 = 2054233^2 + 437318^2 .

It is a cyclic number.

It is not a de Polignac number, because 4411120251413 - 22 = 4411120251409 is a prime.

It is a super-3 number, since 3×44111202514133 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4411120251463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2205560125706 + 2205560125707.

It is an arithmetic number, because the mean of its divisors is an integer number (2205560125707).

Almost surely, 24411120251413 is an apocalyptic number.

It is an amenable number.

4411120251413 is a deficient number, since it is larger than the sum of its proper divisors (1).

4411120251413 is an equidigital number, since it uses as much as digits as its factorization.

4411120251413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 4411120251413 its reverse (3141520211144), we get a palindrome (7552640462557).

The spelling of 4411120251413 in words is "four trillion, four hundred eleven billion, one hundred twenty million, two hundred fifty-one thousand, four hundred thirteen".