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44113312001273 is a prime number
BaseRepresentation
bin10100000011110111011100…
…10010101010110011111001
312210012012011120010210020112
422001323232102222303321
521240223030333020043
6233453213055434105
712202036665135524
oct1201735622526371
9183165146123215
1044113312001273
1113068394658389
124b45556b25935
131b7cb37ab4b58
14ac714a81dbbb
1551774d943518
hex281eee4aacf9

44113312001273 has 2 divisors, whose sum is σ = 44113312001274. Its totient is φ = 44113312001272.

The previous prime is 44113312001263. The next prime is 44113312001347. The reversal of 44113312001273 is 37210021331144.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33312440086249 + 10800871915024 = 5771693^2 + 3286468^2 .

It is a cyclic number.

It is not a de Polignac number, because 44113312001273 - 24 = 44113312001257 is a prime.

It is not a weakly prime, because it can be changed into another prime (44113312001243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22056656000636 + 22056656000637.

It is an arithmetic number, because the mean of its divisors is an integer number (22056656000637).

Almost surely, 244113312001273 is an apocalyptic number.

It is an amenable number.

44113312001273 is a deficient number, since it is larger than the sum of its proper divisors (1).

44113312001273 is an equidigital number, since it uses as much as digits as its factorization.

44113312001273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 32.

The spelling of 44113312001273 in words is "forty-four trillion, one hundred thirteen billion, three hundred twelve million, one thousand, two hundred seventy-three".