Base | Representation |
---|---|
bin | 10100000011110111011100… |
… | …10010101010110011111001 |
3 | 12210012012011120010210020112 |
4 | 22001323232102222303321 |
5 | 21240223030333020043 |
6 | 233453213055434105 |
7 | 12202036665135524 |
oct | 1201735622526371 |
9 | 183165146123215 |
10 | 44113312001273 |
11 | 13068394658389 |
12 | 4b45556b25935 |
13 | 1b7cb37ab4b58 |
14 | ac714a81dbbb |
15 | 51774d943518 |
hex | 281eee4aacf9 |
44113312001273 has 2 divisors, whose sum is σ = 44113312001274. Its totient is φ = 44113312001272.
The previous prime is 44113312001263. The next prime is 44113312001347. The reversal of 44113312001273 is 37210021331144.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 33312440086249 + 10800871915024 = 5771693^2 + 3286468^2 .
It is a cyclic number.
It is not a de Polignac number, because 44113312001273 - 24 = 44113312001257 is a prime.
It is not a weakly prime, because it can be changed into another prime (44113312001243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22056656000636 + 22056656000637.
It is an arithmetic number, because the mean of its divisors is an integer number (22056656000637).
Almost surely, 244113312001273 is an apocalyptic number.
It is an amenable number.
44113312001273 is a deficient number, since it is larger than the sum of its proper divisors (1).
44113312001273 is an equidigital number, since it uses as much as digits as its factorization.
44113312001273 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 32.
The spelling of 44113312001273 in words is "forty-four trillion, one hundred thirteen billion, three hundred twelve million, one thousand, two hundred seventy-three".
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