Base | Representation |
---|---|
bin | 110010001001101010100111… |
… | …1000010110010000001100001 |
3 | 2010211220220200202101122101221 |
4 | 1210103111033002302001201 |
5 | 430310011113231242423 |
6 | 4202113431511055041 |
7 | 161626550000145313 |
oct | 14423251702620141 |
9 | 2124826622348357 |
10 | 441133122134113 |
11 | 118616563145312 |
12 | 4158667a071481 |
13 | 15c1b8a0a604b6 |
14 | 7ad0d581517b3 |
15 | 35eed41591e5d |
hex | 191354f0b2061 |
441133122134113 has 2 divisors, whose sum is σ = 441133122134114. Its totient is φ = 441133122134112.
The previous prime is 441133122134077. The next prime is 441133122134141. The reversal of 441133122134113 is 311431221331144.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 295744100572944 + 145389021561169 = 17197212^2 + 12057737^2 .
It is a cyclic number.
It is not a de Polignac number, because 441133122134113 - 29 = 441133122133601 is a prime.
It is not a weakly prime, because it can be changed into another prime (441133122134143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220566561067056 + 220566561067057.
It is an arithmetic number, because the mean of its divisors is an integer number (220566561067057).
Almost surely, 2441133122134113 is an apocalyptic number.
It is an amenable number.
441133122134113 is a deficient number, since it is larger than the sum of its proper divisors (1).
441133122134113 is an equidigital number, since it uses as much as digits as its factorization.
441133122134113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20736, while the sum is 34.
Adding to 441133122134113 its reverse (311431221331144), we get a palindrome (752564343465257).
The spelling of 441133122134113 in words is "four hundred forty-one trillion, one hundred thirty-three billion, one hundred twenty-two million, one hundred thirty-four thousand, one hundred thirteen".
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