Base | Representation |
---|---|
bin | 1100110101101100010… |
… | …11110001000101001001 |
3 | 1120011200000202120222121 |
4 | 12122312023301011021 |
5 | 24211430124431441 |
6 | 534354113451241 |
7 | 43604640230416 |
oct | 6326613610511 |
9 | 1504600676877 |
10 | 441143202121 |
11 | 1600a6923086 |
12 | 715b5b70b21 |
13 | 327a44b975b |
14 | 174cc51710d |
15 | b71d94bdd1 |
hex | 66b62f1149 |
441143202121 has 2 divisors, whose sum is σ = 441143202122. Its totient is φ = 441143202120.
The previous prime is 441143202113. The next prime is 441143202131. The reversal of 441143202121 is 121202341144.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 321983614096 + 119159588025 = 567436^2 + 345195^2 .
It is a cyclic number.
It is not a de Polignac number, because 441143202121 - 23 = 441143202113 is a prime.
It is not a weakly prime, because it can be changed into another prime (441143202131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220571601060 + 220571601061.
It is an arithmetic number, because the mean of its divisors is an integer number (220571601061).
Almost surely, 2441143202121 is an apocalyptic number.
It is an amenable number.
441143202121 is a deficient number, since it is larger than the sum of its proper divisors (1).
441143202121 is an equidigital number, since it uses as much as digits as its factorization.
441143202121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 441143202121 its reverse (121202341144), we get a palindrome (562345543265).
The spelling of 441143202121 in words is "four hundred forty-one billion, one hundred forty-three million, two hundred two thousand, one hundred twenty-one".
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