Base | Representation |
---|---|
bin | 10100000100001000010000… |
… | …00000001111000001111111 |
3 | 12210020001110021022210211211 |
4 | 22002010020000033001333 |
5 | 21240400014311423403 |
6 | 233501304201425251 |
7 | 12202506360042415 |
oct | 1202041000170177 |
9 | 183201407283754 |
10 | 44122333311103 |
11 | 130711a3983a43 |
12 | 4b4725419b227 |
13 | 1b80944ab67c8 |
14 | ac77649c12b5 |
15 | 517aca92e06d |
hex | 28210800f07f |
44122333311103 has 2 divisors, whose sum is σ = 44122333311104. Its totient is φ = 44122333311102.
The previous prime is 44122333311059. The next prime is 44122333311127. The reversal of 44122333311103 is 30111333322144.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 44122333311103 - 241 = 41923310055551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44122333315103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22061166655551 + 22061166655552.
It is an arithmetic number, because the mean of its divisors is an integer number (22061166655552).
Almost surely, 244122333311103 is an apocalyptic number.
44122333311103 is a deficient number, since it is larger than the sum of its proper divisors (1).
44122333311103 is an equidigital number, since it uses as much as digits as its factorization.
44122333311103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 44122333311103 its reverse (30111333322144), we get a palindrome (74233666633247).
The spelling of 44122333311103 in words is "forty-four trillion, one hundred twenty-two billion, three hundred thirty-three million, three hundred eleven thousand, one hundred three".
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