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441343649609 is a prime number
BaseRepresentation
bin1100110110000100010…
…00011010011101001001
31120012011222221101020122
412123002020122131021
524212332433241414
6534430034033025
743612623060422
oct6330210323511
91505158841218
10441343649609
11160199a91265
1271651118775
1332806b9c635
141750adb4649
15b731343b8e
hex66c221a749

441343649609 has 2 divisors, whose sum is σ = 441343649610. Its totient is φ = 441343649608.

The previous prime is 441343649543. The next prime is 441343649651. The reversal of 441343649609 is 906946343144.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 439134179584 + 2209470025 = 662672^2 + 47005^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-441343649609 is a prime.

It is not a weakly prime, because it can be changed into another prime (441343649309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220671824804 + 220671824805.

It is an arithmetic number, because the mean of its divisors is an integer number (220671824805).

Almost surely, 2441343649609 is an apocalyptic number.

It is an amenable number.

441343649609 is a deficient number, since it is larger than the sum of its proper divisors (1).

441343649609 is an equidigital number, since it uses as much as digits as its factorization.

441343649609 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6718464, while the sum is 53.

The spelling of 441343649609 in words is "four hundred forty-one billion, three hundred forty-three million, six hundred forty-nine thousand, six hundred nine".