Base | Representation |
---|---|
bin | 1100110110111111101… |
… | …01111010001000111101 |
3 | 1120020110201220001101201 |
4 | 12123133311322020331 |
5 | 24214343040141013 |
6 | 534551321535501 |
7 | 43631155003606 |
oct | 6333765721075 |
9 | 1506421801351 |
10 | 441842115133 |
11 | 16042539a841 |
12 | 71770044591 |
13 | 32886238153 |
14 | 1755728adad |
15 | b75eea73dd |
hex | 66dfd7a23d |
441842115133 has 2 divisors, whose sum is σ = 441842115134. Its totient is φ = 441842115132.
The previous prime is 441842115041. The next prime is 441842115163. The reversal of 441842115133 is 331511248144.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 345963946969 + 95878168164 = 588187^2 + 309642^2 .
It is a cyclic number.
It is not a de Polignac number, because 441842115133 - 29 = 441842114621 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 441842115092 and 441842115101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (441842115163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220921057566 + 220921057567.
It is an arithmetic number, because the mean of its divisors is an integer number (220921057567).
Almost surely, 2441842115133 is an apocalyptic number.
It is an amenable number.
441842115133 is a deficient number, since it is larger than the sum of its proper divisors (1).
441842115133 is an equidigital number, since it uses as much as digits as its factorization.
441842115133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 46080, while the sum is 37.
The spelling of 441842115133 in words is "four hundred forty-one billion, eight hundred forty-two million, one hundred fifteen thousand, one hundred thirty-three".
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