Base | Representation |
---|---|
bin | 110010010010010011010100… |
… | …0010101111011100110100011 |
3 | 2011000010101022111101110221121 |
4 | 1210210212220111323212203 |
5 | 430433432411003100003 |
6 | 4204423003413433111 |
7 | 162111365500455253 |
oct | 14444465025734643 |
9 | 2130111274343847 |
10 | 442320031300003 |
11 | 118a33965455a3a |
12 | 4173870363b797 |
13 | 15ca67a51c19cc |
14 | 7b32591c27963 |
15 | 3620b5bd86cbd |
hex | 19249a857b9a3 |
442320031300003 has 2 divisors, whose sum is σ = 442320031300004. Its totient is φ = 442320031300002.
The previous prime is 442320031299953. The next prime is 442320031300019. The reversal of 442320031300003 is 300003130023244.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-442320031300003 is a prime.
It is a super-2 number, since 2×4423200313000032 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (442320031370003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221160015650001 + 221160015650002.
It is an arithmetic number, because the mean of its divisors is an integer number (221160015650002).
Almost surely, 2442320031300003 is an apocalyptic number.
442320031300003 is a deficient number, since it is larger than the sum of its proper divisors (1).
442320031300003 is an equidigital number, since it uses as much as digits as its factorization.
442320031300003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 442320031300003 its reverse (300003130023244), we get a palindrome (742323161323247).
The spelling of 442320031300003 in words is "four hundred forty-two trillion, three hundred twenty billion, thirty-one million, three hundred thousand, three".
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