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44232412122131 is a prime number
BaseRepresentation
bin10100000111010101010010…
…01101100100110000010011
312210121120120212000210121212
422003222221031210300103
521244200440000402011
6234024031204410335
712213454256354552
oct1203525115446023
9183546525023555
1044232412122131
1113103951562a32
124b646553a69ab
131b8b13871884c
14accc0843bd99
1551a8be8e308b
hex283aa9364c13

44232412122131 has 2 divisors, whose sum is σ = 44232412122132. Its totient is φ = 44232412122130.

The previous prime is 44232412122113. The next prime is 44232412122137. The reversal of 44232412122131 is 13122121423244.

Together with previous prime (44232412122113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-44232412122131 is a prime.

It is a super-2 number, since 2×442324121221312 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (44232412122137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22116206061065 + 22116206061066.

It is an arithmetic number, because the mean of its divisors is an integer number (22116206061066).

Almost surely, 244232412122131 is an apocalyptic number.

44232412122131 is a deficient number, since it is larger than the sum of its proper divisors (1).

44232412122131 is an equidigital number, since it uses as much as digits as its factorization.

44232412122131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 18432, while the sum is 32.

Adding to 44232412122131 its reverse (13122121423244), we get a palindrome (57354533545375).

The spelling of 44232412122131 in words is "forty-four trillion, two hundred thirty-two billion, four hundred twelve million, one hundred twenty-two thousand, one hundred thirty-one".