Base | Representation |
---|---|
bin | 100000001011110001010… |
… | …1011001000011011100001 |
3 | 120122212101002001112111121 |
4 | 1000113202223020123201 |
5 | 1034432432010230441 |
6 | 13224014103012241 |
7 | 634401046142521 |
oct | 100274253103341 |
9 | 16585332045447 |
10 | 4423324305121 |
11 | 1455a15288697 |
12 | 5b532a43a081 |
13 | 26116b753847 |
14 | 1141390cd681 |
15 | 7a0da3c3dd1 |
hex | 405e2ac86e1 |
4423324305121 has 2 divisors, whose sum is σ = 4423324305122. Its totient is φ = 4423324305120.
The previous prime is 4423324305061. The next prime is 4423324305151. The reversal of 4423324305121 is 1215034233244.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4344327333025 + 78996972096 = 2084305^2 + 281064^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4423324305121 is a prime.
It is not a weakly prime, because it can be changed into another prime (4423324305151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2211662152560 + 2211662152561.
It is an arithmetic number, because the mean of its divisors is an integer number (2211662152561).
Almost surely, 24423324305121 is an apocalyptic number.
It is an amenable number.
4423324305121 is a deficient number, since it is larger than the sum of its proper divisors (1).
4423324305121 is an equidigital number, since it uses as much as digits as its factorization.
4423324305121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 34.
Adding to 4423324305121 its reverse (1215034233244), we get a palindrome (5638358538365).
The spelling of 4423324305121 in words is "four trillion, four hundred twenty-three billion, three hundred twenty-four million, three hundred five thousand, one hundred twenty-one".
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