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4424234220137 is a prime number
BaseRepresentation
bin100000001100001100011…
…1010001011101001101001
3120122221201111020000020202
41000120120322023221221
51034441312430021022
613224244245401545
7634432435245134
oct100303072135151
916587644200222
104424234220137
111456341972276
125b55431092b5
1326128510c1b4
141141c3cab21b
157a14020d592
hex40618e8ba69

4424234220137 has 2 divisors, whose sum is σ = 4424234220138. Its totient is φ = 4424234220136.

The previous prime is 4424234220053. The next prime is 4424234220163. The reversal of 4424234220137 is 7310224324244.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4026299086096 + 397935134041 = 2006564^2 + 630821^2 .

It is a cyclic number.

It is not a de Polignac number, because 4424234220137 - 212 = 4424234216041 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4424234220137.

It is not a weakly prime, because it can be changed into another prime (4424234222137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2212117110068 + 2212117110069.

It is an arithmetic number, because the mean of its divisors is an integer number (2212117110069).

Almost surely, 24424234220137 is an apocalyptic number.

It is an amenable number.

4424234220137 is a deficient number, since it is larger than the sum of its proper divisors (1).

4424234220137 is an equidigital number, since it uses as much as digits as its factorization.

4424234220137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 258048, while the sum is 38.

The spelling of 4424234220137 in words is "four trillion, four hundred twenty-four billion, two hundred thirty-four million, two hundred twenty thousand, one hundred thirty-seven".