Base | Representation |
---|---|
bin | 1100111000000101001… |
… | …10111101111111101001 |
3 | 1120021222101110001121212 |
4 | 12130002212331333221 |
5 | 24222041400320241 |
6 | 535125235442505 |
7 | 43651466601461 |
oct | 6340246757751 |
9 | 1507871401555 |
10 | 442425401321 |
11 | 1606a4672342 |
12 | 718b3456435 |
13 | 3294a0312c7 |
14 | 175b0922ba1 |
15 | b7962c2beb |
hex | 67029bdfe9 |
442425401321 has 2 divisors, whose sum is σ = 442425401322. Its totient is φ = 442425401320.
The previous prime is 442425401273. The next prime is 442425401381. The reversal of 442425401321 is 123104524244.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 373151161321 + 69274240000 = 610861^2 + 263200^2 .
It is a cyclic number.
It is not a de Polignac number, because 442425401321 - 214 = 442425384937 is a prime.
It is not a weakly prime, because it can be changed into another prime (442425401381) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221212700660 + 221212700661.
It is an arithmetic number, because the mean of its divisors is an integer number (221212700661).
Almost surely, 2442425401321 is an apocalyptic number.
It is an amenable number.
442425401321 is a deficient number, since it is larger than the sum of its proper divisors (1).
442425401321 is an equidigital number, since it uses as much as digits as its factorization.
442425401321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30720, while the sum is 32.
Adding to 442425401321 its reverse (123104524244), we get a palindrome (565529925565).
The spelling of 442425401321 in words is "four hundred forty-two billion, four hundred twenty-five million, four hundred one thousand, three hundred twenty-one".
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