Base | Representation |
---|---|
bin | 11010011010010… |
… | …010101110001001 |
3 | 1010212202210222122 |
4 | 122122102232021 |
5 | 1401413200131 |
6 | 111545101025 |
7 | 13660200566 |
oct | 3232225611 |
9 | 1125683878 |
10 | 443100041 |
11 | 20813368a |
12 | 104487775 |
13 | 70a52197 |
14 | 42bc386d |
15 | 28d78d7b |
hex | 1a692b89 |
443100041 has 2 divisors, whose sum is σ = 443100042. Its totient is φ = 443100040.
The previous prime is 443100017. The next prime is 443100043. The reversal of 443100041 is 140001344.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 322561600 + 120538441 = 17960^2 + 10979^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-443100041 is a prime.
It is a Sophie Germain prime.
Together with 443100043, it forms a pair of twin primes.
It is a Chen prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 443099992 and 443100019.
It is not a weakly prime, because it can be changed into another prime (443100043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221550020 + 221550021.
It is an arithmetic number, because the mean of its divisors is an integer number (221550021).
Almost surely, 2443100041 is an apocalyptic number.
It is an amenable number.
443100041 is a deficient number, since it is larger than the sum of its proper divisors (1).
443100041 is an equidigital number, since it uses as much as digits as its factorization.
443100041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 17.
The square root of 443100041 is about 21049.9415913679. The cubic root of 443100041 is about 762.3725723096.
Adding to 443100041 its reverse (140001344), we get a palindrome (583101385).
The spelling of 443100041 in words is "four hundred forty-three million, one hundred thousand, forty-one".
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