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44310211130021 is a prime number
BaseRepresentation
bin10100001001100110001100…
…11001001111001010100101
312210220000101210120220001112
422010303012121033022211
521301434303022130041
6234123455135234405
712222210224125544
oct1204630631171245
9183800353526045
1044310211130021
1113133945022071
124b77748078a05
131b95586862565
14ad28a8b5c15b
1551c924a4adeb
hex284cc664f2a5

44310211130021 has 2 divisors, whose sum is σ = 44310211130022. Its totient is φ = 44310211130020.

The previous prime is 44310211129991. The next prime is 44310211130027. The reversal of 44310211130021 is 12003111201344.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22684130481796 + 21626080648225 = 4762786^2 + 4650385^2 .

It is a cyclic number.

It is not a de Polignac number, because 44310211130021 - 26 = 44310211129957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44310211130027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22155105565010 + 22155105565011.

It is an arithmetic number, because the mean of its divisors is an integer number (22155105565011).

Almost surely, 244310211130021 is an apocalyptic number.

It is an amenable number.

44310211130021 is a deficient number, since it is larger than the sum of its proper divisors (1).

44310211130021 is an equidigital number, since it uses as much as digits as its factorization.

44310211130021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 44310211130021 its reverse (12003111201344), we get a palindrome (56313322331365).

The spelling of 44310211130021 in words is "forty-four trillion, three hundred ten billion, two hundred eleven million, one hundred thirty thousand, twenty-one".