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44311114240142 = 2233726034732221
BaseRepresentation
bin10100001001100111111000…
…01110010101000010001110
312210220002201201221122020112
422010303330032111002032
521301443130221141032
6234124124520120022
712222241501336631
oct1204637416250216
9183802651848215
1044311114240142
1113134268889072
124b7795a606012
131b9569b9a7749
14ad2952a87c18
1551c978e8e1b2
hex284cfc39508e

44311114240142 has 16 divisors (see below), whose sum is σ = 71231027359392. Its totient is φ = 20619507918240.

The previous prime is 44311114240139. The next prime is 44311114240147. The reversal of 44311114240142 is 24104241111344.

It is a junction number, because it is equal to n+sod(n) for n = 44311114240099 and 44311114240108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (44311114240147) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13017364409 + ... + 13017367812.

It is an arithmetic number, because the mean of its divisors is an integer number (4451939209962).

Almost surely, 244311114240142 is an apocalyptic number.

44311114240142 is a deficient number, since it is larger than the sum of its proper divisors (26919913119250).

44311114240142 is a wasteful number, since it uses less digits than its factorization.

44311114240142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26034732283.

The product of its (nonzero) digits is 12288, while the sum is 32.

Adding to 44311114240142 its reverse (24104241111344), we get a palindrome (68415355351486).

The spelling of 44311114240142 in words is "forty-four trillion, three hundred eleven billion, one hundred fourteen million, two hundred forty thousand, one hundred forty-two".

Divisors: 1 2 23 37 46 74 851 1702 26034732221 52069464442 598798841083 963285092177 1197597682166 1926570184354 22155557120071 44311114240142