Base | Representation |
---|---|
bin | 10100001001101000010000… |
… | …00001001001111000111011 |
3 | 12210220010020112021122001201 |
4 | 22010310020001021320323 |
5 | 21301444031400110321 |
6 | 234124200305155031 |
7 | 12222246423255223 |
oct | 1204641001117073 |
9 | 183803215248051 |
10 | 44311312113211 |
11 | 1313435a549030 |
12 | 4b779b492ba77 |
13 | 1b957009988c0 |
14 | ad2971075083 |
15 | 51c98b528291 |
hex | 284d08049e3b |
44311312113211 has 32 divisors (see below), whose sum is σ = 52928108287488. Its totient is φ = 36567917379840.
The previous prime is 44311312113209. The next prime is 44311312113217. The reversal of 44311312113211 is 11231121311344.
It is not a de Polignac number, because 44311312113211 - 21 = 44311312113209 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 44311312113211.
It is not an unprimeable number, because it can be changed into a prime (44311312113217) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8473015 + ... + 12665488.
It is an arithmetic number, because the mean of its divisors is an integer number (1654003383984).
Almost surely, 244311312113211 is an apocalyptic number.
44311312113211 is a deficient number, since it is larger than the sum of its proper divisors (8616796174277).
44311312113211 is a wasteful number, since it uses less digits than its factorization.
44311312113211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21138771.
The product of its digits is 1728, while the sum is 28.
Adding to 44311312113211 its reverse (11231121311344), we get a palindrome (55542433424555).
The spelling of 44311312113211 in words is "forty-four trillion, three hundred eleven billion, three hundred twelve million, one hundred thirteen thousand, two hundred eleven".
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