Base | Representation |
---|---|
bin | 10100001001101000010000… |
… | …00001001001111001000001 |
3 | 12210220010020112021122001221 |
4 | 22010310020001021321001 |
5 | 21301444031400110332 |
6 | 234124200305155041 |
7 | 12222246423255232 |
oct | 1204641001117101 |
9 | 183803215248057 |
10 | 44311312113217 |
11 | 1313435a549036 |
12 | 4b779b492ba81 |
13 | 1b957009988c6 |
14 | ad2971075089 |
15 | 51c98b528297 |
hex | 284d08049e41 |
44311312113217 has 2 divisors, whose sum is σ = 44311312113218. Its totient is φ = 44311312113216.
The previous prime is 44311312113209. The next prime is 44311312113241. The reversal of 44311312113217 is 71231121311344.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32587097837121 + 11724214276096 = 5708511^2 + 3424064^2 .
It is a cyclic number.
It is not a de Polignac number, because 44311312113217 - 23 = 44311312113209 is a prime.
It is not a weakly prime, because it can be changed into another prime (44311312113247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22155656056608 + 22155656056609.
It is an arithmetic number, because the mean of its divisors is an integer number (22155656056609).
Almost surely, 244311312113217 is an apocalyptic number.
It is an amenable number.
44311312113217 is a deficient number, since it is larger than the sum of its proper divisors (1).
44311312113217 is an equidigital number, since it uses as much as digits as its factorization.
44311312113217 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12096, while the sum is 34.
The spelling of 44311312113217 in words is "forty-four trillion, three hundred eleven billion, three hundred twelve million, one hundred thirteen thousand, two hundred seventeen".
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