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44312014013 is a prime number
BaseRepresentation
bin101001010001001100…
…111010110010111101
311020101011212112201012
4221101030322302331
51211222333422023
632205012125005
73126043622141
oct512114726275
9136334775635
1044312014013
1117879a81a93
128708006765
13424251a247
142205141221
151245340978
hexa5133acbd

44312014013 has 2 divisors, whose sum is σ = 44312014014. Its totient is φ = 44312014012.

The previous prime is 44312013973. The next prime is 44312014027. The reversal of 44312014013 is 31041021344.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44242074244 + 69939769 = 210338^2 + 8363^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-44312014013 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 44312014013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44312044013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22156007006 + 22156007007.

It is an arithmetic number, because the mean of its divisors is an integer number (22156007007).

Almost surely, 244312014013 is an apocalyptic number.

It is an amenable number.

44312014013 is a deficient number, since it is larger than the sum of its proper divisors (1).

44312014013 is an equidigital number, since it uses as much as digits as its factorization.

44312014013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 44312014013 its reverse (31041021344), we get a palindrome (75353035357).

The spelling of 44312014013 in words is "forty-four billion, three hundred twelve million, fourteen thousand, thirteen".