Base | Representation |
---|---|
bin | 110010011000001000010101… |
… | …1110101111101110100000011 |
3 | 2011002221222000110011110100021 |
4 | 1210300100223311331310003 |
5 | 431040044003431230034 |
6 | 4210235005042434311 |
7 | 162223304660306005 |
oct | 14460205365756403 |
9 | 2132858013143307 |
10 | 443121101430019 |
11 | 119212670683201 |
12 | 41847a08362997 |
13 | 160341a9a912bc |
14 | 7b5d266354375 |
15 | 36368e40ae6b4 |
hex | 193042bd7dd03 |
443121101430019 has 2 divisors, whose sum is σ = 443121101430020. Its totient is φ = 443121101430018.
The previous prime is 443121101429999. The next prime is 443121101430023. The reversal of 443121101430019 is 910034101121344.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 443121101430019 - 27 = 443121101429891 is a prime.
It is a super-2 number, since 2×4431211014300192 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (443121101430079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221560550715009 + 221560550715010.
It is an arithmetic number, because the mean of its divisors is an integer number (221560550715010).
Almost surely, 2443121101430019 is an apocalyptic number.
443121101430019 is a deficient number, since it is larger than the sum of its proper divisors (1).
443121101430019 is an equidigital number, since it uses as much as digits as its factorization.
443121101430019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 34.
The spelling of 443121101430019 in words is "four hundred forty-three trillion, one hundred twenty-one billion, one hundred one million, four hundred thirty thousand, nineteen".
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