Base | Representation |
---|---|
bin | 10100001001101001110100… |
… | …00001111110101000001111 |
3 | 12210220012102000011011001222 |
4 | 22010310322001332220033 |
5 | 21302002241201040111 |
6 | 234124415441353555 |
7 | 12222306262303304 |
oct | 1204647201765017 |
9 | 183805360134058 |
10 | 44312151190031 |
11 | 1313475014994a |
12 | 4b77ba99388bb |
13 | 1b9580578106a |
14 | ad2a106930ab |
15 | 51c9da01d7db |
hex | 284d3a07ea0f |
44312151190031 has 2 divisors, whose sum is σ = 44312151190032. Its totient is φ = 44312151190030.
The previous prime is 44312151189997. The next prime is 44312151190049. The reversal of 44312151190031 is 13009115121344.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 44312151190031 - 218 = 44312150927887 is a prime.
It is a super-2 number, since 2×443121511900312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 44312151189973 and 44312151190000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44312151190631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22156075595015 + 22156075595016.
It is an arithmetic number, because the mean of its divisors is an integer number (22156075595016).
Almost surely, 244312151190031 is an apocalyptic number.
44312151190031 is a deficient number, since it is larger than the sum of its proper divisors (1).
44312151190031 is an equidigital number, since it uses as much as digits as its factorization.
44312151190031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 35.
The spelling of 44312151190031 in words is "forty-four trillion, three hundred twelve billion, one hundred fifty-one million, one hundred ninety thousand, thirty-one".
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