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44312151190031 is a prime number
BaseRepresentation
bin10100001001101001110100…
…00001111110101000001111
312210220012102000011011001222
422010310322001332220033
521302002241201040111
6234124415441353555
712222306262303304
oct1204647201765017
9183805360134058
1044312151190031
111313475014994a
124b77ba99388bb
131b9580578106a
14ad2a106930ab
1551c9da01d7db
hex284d3a07ea0f

44312151190031 has 2 divisors, whose sum is σ = 44312151190032. Its totient is φ = 44312151190030.

The previous prime is 44312151189997. The next prime is 44312151190049. The reversal of 44312151190031 is 13009115121344.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 44312151190031 - 218 = 44312150927887 is a prime.

It is a super-2 number, since 2×443121511900312 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 44312151189973 and 44312151190000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44312151190631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22156075595015 + 22156075595016.

It is an arithmetic number, because the mean of its divisors is an integer number (22156075595016).

Almost surely, 244312151190031 is an apocalyptic number.

44312151190031 is a deficient number, since it is larger than the sum of its proper divisors (1).

44312151190031 is an equidigital number, since it uses as much as digits as its factorization.

44312151190031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 35.

The spelling of 44312151190031 in words is "forty-four trillion, three hundred twelve billion, one hundred fifty-one million, one hundred ninety thousand, thirty-one".