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4431223122013 is a prime number
BaseRepresentation
bin100000001111011100101…
…1110101110100001011101
3120200121202120002000021101
41000132321132232201131
51040100121104401023
613231401550033101
7635100561032302
oct100367136564135
916617676060241
104431223122013
1114592a8a26736
125b69737a8791
13261b2a02a7ac
141146881790a9
157a3eda841ad
hex407b97ae85d

4431223122013 has 2 divisors, whose sum is σ = 4431223122014. Its totient is φ = 4431223122012.

The previous prime is 4431223121981. The next prime is 4431223122023. The reversal of 4431223122013 is 3102213221344.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3428415153604 + 1002807968409 = 1851598^2 + 1001403^2 .

It is a cyclic number.

It is not a de Polignac number, because 4431223122013 - 25 = 4431223121981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4431223122023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215611561006 + 2215611561007.

It is an arithmetic number, because the mean of its divisors is an integer number (2215611561007).

Almost surely, 24431223122013 is an apocalyptic number.

It is an amenable number.

4431223122013 is a deficient number, since it is larger than the sum of its proper divisors (1).

4431223122013 is an equidigital number, since it uses as much as digits as its factorization.

4431223122013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 4431223122013 its reverse (3102213221344), we get a palindrome (7533436343357).

The spelling of 4431223122013 in words is "four trillion, four hundred thirty-one billion, two hundred twenty-three million, one hundred twenty-two thousand, thirteen".