Base | Representation |
---|---|
bin | 110010011000001000111101… |
… | …0100000001110100010110010 |
3 | 2011002222002102102102020100202 |
4 | 1210300101322200032202302 |
5 | 431040104204302201232 |
6 | 4210235344024315202 |
7 | 162223352453503013 |
oct | 14460217240164262 |
9 | 2132862372366322 |
10 | 443122421131442 |
11 | 119213188607438 |
12 | 41848116312b02 |
13 | 1603435a306810 |
14 | 7b5d34d72300a |
15 | 363696ed92162 |
hex | 193047a80e8b2 |
443122421131442 has 32 divisors (see below), whose sum is σ = 717547129118400. Its totient is φ = 204022661250240.
The previous prime is 443122421131441. The next prime is 443122421131499. The reversal of 443122421131442 is 244131124221344.
It is a junction number, because it is equal to n+sod(n) for n = 443122421131396 and 443122421131405.
It is not an unprimeable number, because it can be changed into a prime (443122421131441) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 234650309 + ... + 236531207.
It is an arithmetic number, because the mean of its divisors is an integer number (22423347784950).
Almost surely, 2443122421131442 is an apocalyptic number.
443122421131442 is a deficient number, since it is larger than the sum of its proper divisors (274424707986958).
443122421131442 is a wasteful number, since it uses less digits than its factorization.
443122421131442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1902858.
The product of its digits is 147456, while the sum is 38.
Adding to 443122421131442 its reverse (244131124221344), we get a palindrome (687253545352786).
The spelling of 443122421131442 in words is "four hundred forty-three trillion, one hundred twenty-two billion, four hundred twenty-one million, one hundred thirty-one thousand, four hundred forty-two".
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