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443124430121 is a prime number
BaseRepresentation
bin1100111001011000100…
…01100011010100101001
31120100210002210101212102
412130230101203110221
524230004323230441
6535322450223145
744005015336352
oct6345421432451
91510702711772
10443124430121
11160a23208a9a
1271a69584ab5
1332a2bac0609
14176396c6d29
15b7d785269b
hex672c463529

443124430121 has 2 divisors, whose sum is σ = 443124430122. Its totient is φ = 443124430120.

The previous prime is 443124430103. The next prime is 443124430123. The reversal of 443124430121 is 121034421344.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 406323379225 + 36801050896 = 637435^2 + 191836^2 .

It is a cyclic number.

It is not a de Polignac number, because 443124430121 - 230 = 442050688297 is a prime.

It is a super-2 number, since 2×4431244301212 (a number of 24 digits) contains 22 as substring.

Together with 443124430123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (443124430123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221562215060 + 221562215061.

It is an arithmetic number, because the mean of its divisors is an integer number (221562215061).

Almost surely, 2443124430121 is an apocalyptic number.

It is an amenable number.

443124430121 is a deficient number, since it is larger than the sum of its proper divisors (1).

443124430121 is an equidigital number, since it uses as much as digits as its factorization.

443124430121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 443124430121 its reverse (121034421344), we get a palindrome (564158851465).

The spelling of 443124430121 in words is "four hundred forty-three billion, one hundred twenty-four million, four hundred thirty thousand, one hundred twenty-one".