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4431415296013 is a prime number
BaseRepresentation
bin100000001111100010011…
…1011110100000000001101
3120200122020221200110102221
41000133010323310000031
51040101014303433023
613231433013015341
7635105413343326
oct100370473640015
916618227613387
104431415296013
111459397453922
125b6a08024551
13261b5aaa4914
141146a58c144d
157a41089485d
hex407c4ef400d

4431415296013 has 2 divisors, whose sum is σ = 4431415296014. Its totient is φ = 4431415296012.

The previous prime is 4431415295977. The next prime is 4431415296041. The reversal of 4431415296013 is 3106925141344.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4396557659209 + 34857636804 = 2096797^2 + 186702^2 .

It is a cyclic number.

It is not a de Polignac number, because 4431415296013 - 29 = 4431415295501 is a prime.

It is a super-4 number, since 4×44314152960134 (a number of 52 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4431415296043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215707648006 + 2215707648007.

It is an arithmetic number, because the mean of its divisors is an integer number (2215707648007).

Almost surely, 24431415296013 is an apocalyptic number.

It is an amenable number.

4431415296013 is a deficient number, since it is larger than the sum of its proper divisors (1).

4431415296013 is an equidigital number, since it uses as much as digits as its factorization.

4431415296013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 43.

The spelling of 4431415296013 in words is "four trillion, four hundred thirty-one billion, four hundred fifteen million, two hundred ninety-six thousand, thirteen".