Base | Representation |
---|---|
bin | 101001010001010101… |
… | …010011110000101111 |
3 | 11020101100000021201211 |
4 | 221101111103300233 |
5 | 1211223414312143 |
6 | 32205131215251 |
7 | 3126101412334 |
oct | 512125236057 |
9 | 136340007654 |
10 | 44314213423 |
11 | 17880244487 |
12 | 87088a7527 |
13 | 4242b0a37c |
14 | 220555498b |
15 | 124562749d |
hex | a51553c2f |
44314213423 has 2 divisors, whose sum is σ = 44314213424. Its totient is φ = 44314213422.
The previous prime is 44314213369. The next prime is 44314213439. The reversal of 44314213423 is 32431241344.
44314213423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 44314213423 - 29 = 44314212911 is a prime.
It is a super-2 number, since 2×443142134232 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44314214423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22157106711 + 22157106712.
It is an arithmetic number, because the mean of its divisors is an integer number (22157106712).
Almost surely, 244314213423 is an apocalyptic number.
44314213423 is a deficient number, since it is larger than the sum of its proper divisors (1).
44314213423 is an equidigital number, since it uses as much as digits as its factorization.
44314213423 is an evil number, because the sum of its binary digits is even.
The product of its digits is 27648, while the sum is 31.
Adding to 44314213423 its reverse (32431241344), we get a palindrome (76745454767).
The spelling of 44314213423 in words is "forty-four billion, three hundred fourteen million, two hundred thirteen thousand, four hundred twenty-three".
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