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443142531101 is a prime number
BaseRepresentation
bin1100111001011010101…
…10100110100000011101
31120100211100212000202002
412130231112212200131
524230023441443401
6535324334212045
744005325236034
oct6345526464035
91510740760662
10443142531101
11160a32451586
1271a73654025
1332a3278a55a
141763bc7971b
15b7d922aa6b
hex672d5a681d

443142531101 has 2 divisors, whose sum is σ = 443142531102. Its totient is φ = 443142531100.

The previous prime is 443142531079. The next prime is 443142531151. The reversal of 443142531101 is 101135241344.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 391593099076 + 51549432025 = 625774^2 + 227045^2 .

It is a cyclic number.

It is not a de Polignac number, because 443142531101 - 218 = 443142268957 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (443142531151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221571265550 + 221571265551.

It is an arithmetic number, because the mean of its divisors is an integer number (221571265551).

Almost surely, 2443142531101 is an apocalyptic number.

It is an amenable number.

443142531101 is a deficient number, since it is larger than the sum of its proper divisors (1).

443142531101 is an equidigital number, since it uses as much as digits as its factorization.

443142531101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 443142531101 its reverse (101135241344), we get a palindrome (544277772445).

The spelling of 443142531101 in words is "four hundred forty-three billion, one hundred forty-two million, five hundred thirty-one thousand, one hundred one".