Base | Representation |
---|---|
bin | 101001010001010110… |
… | …100101111100000111 |
3 | 11020101100122101110111 |
4 | 221101112211330013 |
5 | 1211224011100043 |
6 | 32205142333451 |
7 | 3126104313562 |
oct | 512126457407 |
9 | 136340571414 |
10 | 44314550023 |
11 | 17880454367 |
12 | 8708a2a287 |
13 | 4242bc7643 |
14 | 22056014d9 |
15 | 124569209d |
hex | a515a5f07 |
44314550023 has 2 divisors, whose sum is σ = 44314550024. Its totient is φ = 44314550022.
The previous prime is 44314549987. The next prime is 44314550069. The reversal of 44314550023 is 32005541344.
44314550023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 44314550023 - 233 = 35724615431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44314550723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22157275011 + 22157275012.
It is an arithmetic number, because the mean of its divisors is an integer number (22157275012).
Almost surely, 244314550023 is an apocalyptic number.
44314550023 is a deficient number, since it is larger than the sum of its proper divisors (1).
44314550023 is an equidigital number, since it uses as much as digits as its factorization.
44314550023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 31.
The spelling of 44314550023 in words is "forty-four billion, three hundred fourteen million, five hundred fifty thousand, twenty-three".
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