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4432303134142 = 213170473197467
BaseRepresentation
bin100000001111111100111…
…0110101001010110111110
3120200201112211022022101121
41000133321312221112332
51040104324100243032
613232101050301154
7635136414006562
oct100377166512676
916621484268347
104432303134142
111459802629844
125b70154277ba
13261c6ca00720
1411474b7936a2
157a4637bca97
hex407f9da95be

4432303134142 has 8 divisors (see below), whose sum is σ = 7159874293656. Its totient is φ = 2045678369592.

The previous prime is 4432303134067. The next prime is 4432303134227. The reversal of 4432303134142 is 2414313032344.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×44323031341422 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4432303134098 and 4432303134107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85236598708 + ... + 85236598759.

It is an arithmetic number, because the mean of its divisors is an integer number (894984286707).

Almost surely, 24432303134142 is an apocalyptic number.

4432303134142 is a deficient number, since it is larger than the sum of its proper divisors (2727571159514).

4432303134142 is a wasteful number, since it uses less digits than its factorization.

4432303134142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 170473197482.

The product of its (nonzero) digits is 82944, while the sum is 34.

Adding to 4432303134142 its reverse (2414313032344), we get a palindrome (6846616166486).

The spelling of 4432303134142 in words is "four trillion, four hundred thirty-two billion, three hundred three million, one hundred thirty-four thousand, one hundred forty-two".

Divisors: 1 2 13 26 170473197467 340946394934 2216151567071 4432303134142