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443240132113 is a prime number
BaseRepresentation
bin1100111001100110010…
…10111010111000010001
31120101002011111200011101
412130303022322320101
524230223433211423
6535342142144401
744010621650062
oct6346312727021
91511064450141
10443240132113
11160a82554679
1271aa0282101
1332a49a7112c
141764ac04569
15b7e2aa97ad
hex67332bae11

443240132113 has 2 divisors, whose sum is σ = 443240132114. Its totient is φ = 443240132112.

The previous prime is 443240132039. The next prime is 443240132117. The reversal of 443240132113 is 311231042344.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 442741190544 + 498941569 = 665388^2 + 22337^2 .

It is a cyclic number.

It is not a de Polignac number, because 443240132113 - 221 = 443238034961 is a prime.

It is not a weakly prime, because it can be changed into another prime (443240132117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221620066056 + 221620066057.

It is an arithmetic number, because the mean of its divisors is an integer number (221620066057).

Almost surely, 2443240132113 is an apocalyptic number.

It is an amenable number.

443240132113 is a deficient number, since it is larger than the sum of its proper divisors (1).

443240132113 is an equidigital number, since it uses as much as digits as its factorization.

443240132113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 443240132113 its reverse (311231042344), we get a palindrome (754471174457).

The spelling of 443240132113 in words is "four hundred forty-three billion, two hundred forty million, one hundred thirty-two thousand, one hundred thirteen".