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44325040354211 is a prime number
BaseRepresentation
bin10100001010000001110100…
…10010001111001110100011
312210221102200021101112101002
422011000322102033032203
521302210140312313321
6234134350433102215
712223243551345401
oct1205007222171643
9183842607345332
1044325040354211
111313a164801751
124b7a5a63b796b
131b96aaabb7126
14ad34b440a471
1551cee187a20b
hex28503a48f3a3

44325040354211 has 2 divisors, whose sum is σ = 44325040354212. Its totient is φ = 44325040354210.

The previous prime is 44325040354103. The next prime is 44325040354229. The reversal of 44325040354211 is 11245304052344.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-44325040354211 is a prime.

It is a super-2 number, since 2×443250403542112 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (44325040354241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22162520177105 + 22162520177106.

It is an arithmetic number, because the mean of its divisors is an integer number (22162520177106).

Almost surely, 244325040354211 is an apocalyptic number.

44325040354211 is a deficient number, since it is larger than the sum of its proper divisors (1).

44325040354211 is an equidigital number, since it uses as much as digits as its factorization.

44325040354211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 230400, while the sum is 38.

The spelling of 44325040354211 in words is "forty-four trillion, three hundred twenty-five billion, forty million, three hundred fifty-four thousand, two hundred eleven".