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443412200334161 is a prime number
BaseRepresentation
bin110010011010001111111001…
…0101100001010001101010001
32011010222210101122002222001102
41210310133302230022031101
5431104331141241143121
64211020430330314145
7162253321453206512
oct14464376254121521
92133883348088042
10443412200334161
111193150703a1433
1241894308888955
131605578b78b686
147b6d39d268a09
15363e2800cb90b
hex19347f2b0a351

443412200334161 has 2 divisors, whose sum is σ = 443412200334162. Its totient is φ = 443412200334160.

The previous prime is 443412200334157. The next prime is 443412200334193. The reversal of 443412200334161 is 161433002214344.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 438147786720400 + 5264413613761 = 20931980^2 + 2294431^2 .

It is a cyclic number.

It is not a de Polignac number, because 443412200334161 - 22 = 443412200334157 is a prime.

It is a super-2 number, since 2×4434122003341612 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (443412200334101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221706100167080 + 221706100167081.

It is an arithmetic number, because the mean of its divisors is an integer number (221706100167081).

Almost surely, 2443412200334161 is an apocalyptic number.

It is an amenable number.

443412200334161 is a deficient number, since it is larger than the sum of its proper divisors (1).

443412200334161 is an equidigital number, since it uses as much as digits as its factorization.

443412200334161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 165888, while the sum is 38.

The spelling of 443412200334161 in words is "four hundred forty-three trillion, four hundred twelve billion, two hundred million, three hundred thirty-four thousand, one hundred sixty-one".