Base | Representation |
---|---|
bin | 100000010000111001000… |
… | …0101100001111111001111 |
3 | 120200220202101222001112102 |
4 | 1000201302011201333033 |
5 | 1040122441444131111 |
6 | 13233033145225315 |
7 | 635240406443534 |
oct | 100416205417717 |
9 | 16626671861472 |
10 | 4434320302031 |
11 | 145a648231944 |
12 | 5b7498a9223b |
13 | 2622018a90a9 |
14 | 11489d63ad8b |
15 | 7a53092213b |
hex | 40872161fcf |
4434320302031 has 2 divisors, whose sum is σ = 4434320302032. Its totient is φ = 4434320302030.
The previous prime is 4434320302003. The next prime is 4434320302057. The reversal of 4434320302031 is 1302030234344.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4434320302031 - 26 = 4434320301967 is a prime.
It is a super-2 number, since 2×44343203020312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4434320301985 and 4434320302003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4434320302001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2217160151015 + 2217160151016.
It is an arithmetic number, because the mean of its divisors is an integer number (2217160151016).
Almost surely, 24434320302031 is an apocalyptic number.
4434320302031 is a deficient number, since it is larger than the sum of its proper divisors (1).
4434320302031 is an equidigital number, since it uses as much as digits as its factorization.
4434320302031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 29.
Adding to 4434320302031 its reverse (1302030234344), we get a palindrome (5736350536375).
The spelling of 4434320302031 in words is "four trillion, four hundred thirty-four billion, three hundred twenty million, three hundred two thousand, thirty-one".
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