Base | Representation |
---|---|
bin | 101001010011000100… |
… | …010011011010111011 |
3 | 11020110100202112202020 |
4 | 221103010103122323 |
5 | 1211303341410021 |
6 | 32212051005523 |
7 | 3126603626130 |
oct | 512304233273 |
9 | 136410675666 |
10 | 44343310011 |
11 | 17895708150 |
12 | 87165998a3 |
13 | 4248b570a0 |
14 | 220936a587 |
15 | 1247e737c6 |
hex | a531136bb |
44343310011 has 32 divisors (see below), whose sum is σ = 79383833088. Its totient is φ = 21263523840.
The previous prime is 44343310009. The next prime is 44343310013. The reversal of 44343310011 is 11001334344.
44343310011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (44343310009) and next prime (44343310013).
It is not a de Polignac number, because 44343310011 - 21 = 44343310009 is a prime.
It is not an unprimeable number, because it can be changed into a prime (44343310013) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7380166 + ... + 7386171.
It is an arithmetic number, because the mean of its divisors is an integer number (2480744784).
Almost surely, 244343310011 is an apocalyptic number.
44343310011 is a deficient number, since it is larger than the sum of its proper divisors (35040523077).
44343310011 is a wasteful number, since it uses less digits than its factorization.
44343310011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14766371.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 44343310011 its reverse (11001334344), we get a palindrome (55344644355).
The spelling of 44343310011 in words is "forty-four billion, three hundred forty-three million, three hundred ten thousand, eleven".
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