Base | Representation |
---|---|
bin | 101001010011000100… |
… | …010100010011001101 |
3 | 11020110100202201200122 |
4 | 221103010110103031 |
5 | 1211303342013423 |
6 | 32212051034325 |
7 | 3126603642464 |
oct | 512304242315 |
9 | 136410681618 |
10 | 44343313613 |
11 | 1789570a925 |
12 | 871659b9a5 |
13 | 4248b58911 |
14 | 220936b9db |
15 | 1247e748c8 |
hex | a531144cd |
44343313613 has 2 divisors, whose sum is σ = 44343313614. Its totient is φ = 44343313612.
The previous prime is 44343313607. The next prime is 44343313639. The reversal of 44343313613 is 31631334344.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23000148964 + 21343164649 = 151658^2 + 146093^2 .
It is a cyclic number.
It is not a de Polignac number, because 44343313613 - 210 = 44343312589 is a prime.
It is a super-2 number, since 2×443433136132 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44343313643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22171656806 + 22171656807.
It is an arithmetic number, because the mean of its divisors is an integer number (22171656807).
Almost surely, 244343313613 is an apocalyptic number.
It is an amenable number.
44343313613 is a deficient number, since it is larger than the sum of its proper divisors (1).
44343313613 is an equidigital number, since it uses as much as digits as its factorization.
44343313613 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 93312, while the sum is 35.
Adding to 44343313613 its reverse (31631334344), we get a palindrome (75974647957).
The spelling of 44343313613 in words is "forty-four billion, three hundred forty-three million, three hundred thirteen thousand, six hundred thirteen".
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