Base | Representation |
---|---|
bin | 100000010000111001111… |
… | …0110111000001110110101 |
3 | 120200220211110212122122001 |
4 | 1000201303312320032311 |
5 | 1040123022100443123 |
6 | 13233040130135301 |
7 | 635241220136503 |
oct | 100416366701665 |
9 | 16626743778561 |
10 | 4434350015413 |
11 | 145a662a86a5a |
12 | 5b74a6a21531 |
13 | 262207ab0786 |
14 | 1148a3573673 |
15 | 7a5333410ad |
hex | 40873db83b5 |
4434350015413 has 2 divisors, whose sum is σ = 4434350015414. Its totient is φ = 4434350015412.
The previous prime is 4434350015393. The next prime is 4434350015441. The reversal of 4434350015413 is 3145100534344.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4428259461649 + 6090553764 = 2104343^2 + 78042^2 .
It is a cyclic number.
It is not a de Polignac number, because 4434350015413 - 237 = 4296911061941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4434350015113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2217175007706 + 2217175007707.
It is an arithmetic number, because the mean of its divisors is an integer number (2217175007707).
Almost surely, 24434350015413 is an apocalyptic number.
It is an amenable number.
4434350015413 is a deficient number, since it is larger than the sum of its proper divisors (1).
4434350015413 is an equidigital number, since it uses as much as digits as its factorization.
4434350015413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 4434350015413 its reverse (3145100534344), we get a palindrome (7579450549757).
The spelling of 4434350015413 in words is "four trillion, four hundred thirty-four billion, three hundred fifty million, fifteen thousand, four hundred thirteen".
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