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4434885523457 is a prime number
BaseRepresentation
bin100000010001001001111…
…0001101011100000000001
3120200222012210112021120022
41000202103301223200001
51040130121143222312
613233205220023225
7635260411652444
oct100422361534001
916628183467508
104434885523457
11145a908296094
125b7616231b15
13262291a1893c
1411491472d65b
157a565370172
hex40893c6b801

4434885523457 has 2 divisors, whose sum is σ = 4434885523458. Its totient is φ = 4434885523456.

The previous prime is 4434885523381. The next prime is 4434885523463. The reversal of 4434885523457 is 7543255884344.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4357806551296 + 77078972161 = 2087536^2 + 277631^2 .

It is a cyclic number.

It is not a de Polignac number, because 4434885523457 - 234 = 4417705654273 is a prime.

It is a super-3 number, since 3×44348855234573 (a number of 39 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4434885523457.

It is not a weakly prime, because it can be changed into another prime (4434885523487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2217442761728 + 2217442761729.

It is an arithmetic number, because the mean of its divisors is an integer number (2217442761729).

Almost surely, 24434885523457 is an apocalyptic number.

It is an amenable number.

4434885523457 is a deficient number, since it is larger than the sum of its proper divisors (1).

4434885523457 is an equidigital number, since it uses as much as digits as its factorization.

4434885523457 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 258048000, while the sum is 62.

The spelling of 4434885523457 in words is "four trillion, four hundred thirty-four billion, eight hundred eighty-five million, five hundred twenty-three thousand, four hundred fifty-seven".