Base | Representation |
---|---|
bin | 101001010011101110… |
… | …000000001001101011 |
3 | 11020111010022220102112 |
4 | 221103232000021223 |
5 | 1211314141204011 |
6 | 32213121152535 |
7 | 3130065554234 |
oct | 512356001153 |
9 | 136433286375 |
10 | 44354241131 |
11 | 178a08a3932 |
12 | 871a18b74b |
13 | 424b1b36c5 |
14 | 220a9b408b |
15 | 1248dd258b |
hex | a53b8026b |
44354241131 has 2 divisors, whose sum is σ = 44354241132. Its totient is φ = 44354241130.
The previous prime is 44354241109. The next prime is 44354241137. The reversal of 44354241131 is 13114245344.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-44354241131 is a prime.
It is a super-2 number, since 2×443542411312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (44354241137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22177120565 + 22177120566.
It is an arithmetic number, because the mean of its divisors is an integer number (22177120566).
Almost surely, 244354241131 is an apocalyptic number.
44354241131 is a deficient number, since it is larger than the sum of its proper divisors (1).
44354241131 is an equidigital number, since it uses as much as digits as its factorization.
44354241131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 23040, while the sum is 32.
Adding to 44354241131 its reverse (13114245344), we get a palindrome (57468486475).
The spelling of 44354241131 in words is "forty-four billion, three hundred fifty-four million, two hundred forty-one thousand, one hundred thirty-one".
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