Base | Representation |
---|---|
bin | 101001010110100000… |
… | …011111100000111111 |
3 | 11020121101101002101012 |
4 | 221112200133200333 |
5 | 1211413130444411 |
6 | 32221512105435 |
7 | 3131204352434 |
oct | 512640374077 |
9 | 136541332335 |
10 | 44401031231 |
11 | 17915251a37 |
12 | 873199527b |
13 | 4257ab6a5b |
14 | 2212cb3b8b |
15 | 124d07618b |
hex | a5681f83f |
44401031231 has 2 divisors, whose sum is σ = 44401031232. Its totient is φ = 44401031230.
The previous prime is 44401031167. The next prime is 44401031243. The reversal of 44401031231 is 13213010444.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 44401031231 - 26 = 44401031167 is a prime.
It is a super-2 number, since 2×444010312312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 44401031197 and 44401031206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44401031291) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22200515615 + 22200515616.
It is an arithmetic number, because the mean of its divisors is an integer number (22200515616).
Almost surely, 244401031231 is an apocalyptic number.
44401031231 is a deficient number, since it is larger than the sum of its proper divisors (1).
44401031231 is an equidigital number, since it uses as much as digits as its factorization.
44401031231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 44401031231 its reverse (13213010444), we get a palindrome (57614041675).
The spelling of 44401031231 in words is "forty-four billion, four hundred one million, thirty-one thousand, two hundred thirty-one".
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