Base | Representation |
---|---|
bin | 10100001100001111100001… |
… | …00000101100001010100111 |
3 | 12211012201000211200120110221 |
4 | 22012013300200230022213 |
5 | 21304431434140240403 |
6 | 234233331141225211 |
7 | 12231605643121240 |
oct | 1206076040541247 |
9 | 184181024616427 |
10 | 44401112040103 |
11 | 13169451237245 |
12 | 4b91296702207 |
13 | 1ba1012209510 |
14 | ad704d571cc7 |
15 | 51ee95033dbd |
hex | 2861f082c2a7 |
44401112040103 has 32 divisors (see below), whose sum is σ = 55379877396480. Its totient is φ = 34661441168640.
The previous prime is 44401112040079. The next prime is 44401112040107. The reversal of 44401112040103 is 30104021110444.
It is not a de Polignac number, because 44401112040103 - 217 = 44401111909031 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (44401112040107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2087463 + ... + 9651928.
It is an arithmetic number, because the mean of its divisors is an integer number (1730621168640).
Almost surely, 244401112040103 is an apocalyptic number.
44401112040103 is a deficient number, since it is larger than the sum of its proper divisors (10978765356377).
44401112040103 is a wasteful number, since it uses less digits than its factorization.
44401112040103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11739967.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 44401112040103 its reverse (30104021110444), we get a palindrome (74505133150547).
The spelling of 44401112040103 in words is "forty-four trillion, four hundred one billion, one hundred twelve million, forty thousand, one hundred three".
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