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444023414437 is a prime number
BaseRepresentation
bin1100111011000011101…
…10111001111010100101
31120110002202101112111211
412131201312321322211
524233324443230222
6535552002431421
744036212515031
oct6354166717245
91513082345454
10444023414437
11161344707239
127207a662571
1332b4311c8b5
14176c2c5b1c1
15b83b72d277
hex6761db9ea5

444023414437 has 2 divisors, whose sum is σ = 444023414438. Its totient is φ = 444023414436.

The previous prime is 444023414369. The next prime is 444023414441. The reversal of 444023414437 is 734414320444.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 427446594436 + 16576820001 = 653794^2 + 128751^2 .

It is a cyclic number.

It is not a de Polignac number, because 444023414437 - 211 = 444023412389 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 444023414437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (444023411437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 222011707218 + 222011707219.

It is an arithmetic number, because the mean of its divisors is an integer number (222011707219).

Almost surely, 2444023414437 is an apocalyptic number.

It is an amenable number.

444023414437 is a deficient number, since it is larger than the sum of its proper divisors (1).

444023414437 is an equidigital number, since it uses as much as digits as its factorization.

444023414437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 516096, while the sum is 40.

The spelling of 444023414437 in words is "four hundred forty-four billion, twenty-three million, four hundred fourteen thousand, four hundred thirty-seven".