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4440323301137 is a prime number
BaseRepresentation
bin100000010011101011111…
…1001001001111100010001
3120201111020202200000012122
41000213113321021330101
51040222240231114022
613235504550304025
7635542231212623
oct100472771117421
916644222600178
104440323301137
111462148820a29
125b8693358015
1326294a484c79
14114cac9cac13
157a78294d742
hex409d7e49f11

4440323301137 has 2 divisors, whose sum is σ = 4440323301138. Its totient is φ = 4440323301136.

The previous prime is 4440323301103. The next prime is 4440323301173. The reversal of 4440323301137 is 7311033230444.

It is a happy number.

Together with next prime (4440323301173) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3717399939136 + 722923362001 = 1928056^2 + 850249^2 .

It is a cyclic number.

It is not a de Polignac number, because 4440323301137 - 242 = 42276790033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4440323301097 and 4440323301106.

It is not a weakly prime, because it can be changed into another prime (4440323601137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2220161650568 + 2220161650569.

It is an arithmetic number, because the mean of its divisors is an integer number (2220161650569).

Almost surely, 24440323301137 is an apocalyptic number.

It is an amenable number.

4440323301137 is a deficient number, since it is larger than the sum of its proper divisors (1).

4440323301137 is an equidigital number, since it uses as much as digits as its factorization.

4440323301137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72576, while the sum is 35.

The spelling of 4440323301137 in words is "four trillion, four hundred forty billion, three hundred twenty-three million, three hundred one thousand, one hundred thirty-seven".